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March 28, 2017

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In the formula A(t) = A0ekt, A is the amount of radioactive material remaining from an
initial amount A0 at a given time t, and k is a negative constant determined by the nature
of the material. An artifact is discovered at a certain site. If it has 72% of the carbon-14 it
originally contained, what is the approximate age of the artifact? (carbon-14 decays at the
rate of 0.0125% annually.) (Round to the nearest year.)

  • algebra 2 - ,

    You are solving

    .72 = 1(e^(-.0125t)
    ln .72= ln (e^(-.0125t))
    -.0125t = ln .72
    t = ln.72/-.0125 = appr. 26.28 years

  • algebra 2 - ,

    radioactive=decay
    convert % to decimal.
    72%=0.72, 0.0125%=0.000125
    A=Aoe^-kt
    0.72A=Aoe^-0.000125t
    0.72=e^-0.000125t
    ln 0.72=ln e^-0.000125t
    ln 0.72=-0.000125t
    ln 0.72/-0.000125=t
    t=2628

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