physics
posted by victor on .
An unmarked police car traveling a constant 90 km/h is passed by a speeder. Precisely 2.00 s after the speeder passes, the police officer steps on the accelerator.
If the police car accelerates uniformly at 2.00 m/s^2 and overtakes the speeder after accelerating for 7.00 s, what was the speeder's speed in km/h?
I got 28.57 m/s (without converting to km/h yet). And I'm not sure if that's correct.

That can't be correct. The speeder must be traveling faster than the police car (90 km/h).

Sorry! I just noticed your answer had not been converted to km/h. You don't show how you got your answer, so it's impossible to tell where you might have made an error.
The answer I get, 29.45 m/2, is close to yours.