Posted by **eekim** on Tuesday, July 12, 2011 at 10:11am.

a man measured the angle of elevation of the top of a tower to be 70 degree. When he walked 300 m. further, the angle of elevation of the top was 35 degree. What is the height of the tower?

- trigonometry -
**Reiny**, Tuesday, July 12, 2011 at 10:41am
make a diagram

label the tower AB , where A is the top of the tower.

label the man's first position C, his second position D

so that DC = 300

Look at triangle ADC,

angle D = 35°

angle ACD = 110° , so then

angle DAC = 35°

so the triangle is isosceles (lucky) and AC = 300

Then in the right-angled triangle ACB ,

sin70 = AB/300

AB = 300sin70 = 281.9 m

(had the triangle not been isosceles, I would have used the Sine Law to find AC )

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