Posted by **hlehle** on Tuesday, July 12, 2011 at 3:19am.

a circuit with 3 resisters {9 ohms 10 ohms and 12 ohms} connected in parallel with the source 150v\50HZ.use kitchoffs law to find the current of the circuit and the current across each resister?

- Electrotechnics N4 -
**Henry**, Wednesday, July 13, 2011 at 7:06pm
R1 = 9 Ohms.

R2 = 10 Ohms.

R3 = 12 Ohms.

1/Rt = 1/R1 + 1/R2 + 1/R3,

1/Rt = 1/9 + 1/10 + 1/12 = 0.294444,

Rt = 3.4 Ohms.

It = E/Rt = 150/3.4 = 44.1A.

I1 + I2 + I3 = It = 44.1A.

Let I3 = I,

I2 = (12/10)*I = 1.2I.

I1 = (12/9)*I = 1.33I.

1.33I + 1.2I + I = 44.1,

3.53I = 44.1,

I = I3 = 12.49A.

1.2I = I2 = 1.2*12.49 = 14.99A.

1.33I = I1 = 1.33*12.49 = 16.61A.

It = I1 + I2 + I3,

It = 16.61 + 14.99 + 12.49 = 44.1A.

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