Friday

March 27, 2015

March 27, 2015

Posted by **Carly** on Monday, July 11, 2011 at 11:33pm.

g(t)= (t^3/2)(e^-2t) for 0<t<1.

- Another Calculus -
**Reiny**, Tuesday, July 12, 2011 at 7:55amUsing the product rule

g'(t) = t^(3/2)(-2)e^(-2t) + (3/2)t^(1/2)(e^(-2t))

common factor ...

= (1/2)e^(-2t)(t^(1/2)) [-4t + 3}

set this equal to zero

from the first factor we get t=0

and from the second one we get t = 3/4

now evaluate

g(0) = ..

g(3/4) = ..

g(1) = ...

and determine which is the largest and smallest value.

**Answer this Question**

**Related Questions**

Calculus - Find the largest and smallest values of the given function over the ...

Calculus Help!! - Region R is bounded by the functions f(x) = 2(x-4) + pi, g(x...

Calculus IVT - The function f is continuous on the closed interval [0,6] and ...

Calculus HELP!!! - Here is the graph. h t t p : / /goo.gl/PTc2I (spaces added at...

Calculus - 1. Locate the absolute extrema of the function f(x)=cos(pi*x) on the ...

math - Given the function f(x)=x^4−6x^2 a.) Find all values of x where ...

calculus - The function f is continuous on the closed interval [0,2] and has ...

calculus - A region is bounded by the function y=2x^2+3 and the x-axis over the ...

Calculus - The function f(x)=(x^4)-(10x^3)+(18x^2)-8 is continuous on the closed...

Calculus - Determine whether Rolle's Theorem can be applied to f on the closed ...