Posted by **Carly** on Monday, July 11, 2011 at 11:33pm.

Sorry I have been trying to figure this out all day. Find the largest and smallest values of the given function over the prescribed closed, bounded interval.

g(t)= (t^3/2)(e^-2t) for 0<t<1.

## Answer This Question

## Related Questions

- Calculus - Find the largest and smallest values of the given function over the ...
- Calculus Help!! - Region R is bounded by the functions f(x) = 2(x-4) + pi, g(x...
- Calculus IVT - The function f is continuous on the closed interval [0,6] and ...
- Calculus HELP!!! - Here is the graph. h t t p : / /goo.gl/PTc2I (spaces added at...
- Calculus - 1. Locate the absolute extrema of the function f(x)=cos(pi*x) on the ...
- math - Given the function f(x)=x^4−6x^2 a.) Find all values of x where ...
- calculus - The function f is continuous on the closed interval [0,2] and has ...
- Calculus - The function f(x)=(x^4)-(10x^3)+(18x^2)-8 is continuous on the closed...
- calculus - A region is bounded by the function y=2x^2+3 and the x-axis over the ...
- Calculus - Determine whether Rolle's Theorem can be applied to f on the closed ...

More Related Questions