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January 25, 2015

Posted by **kim** on Monday, July 11, 2011 at 3:51pm.

Product X:-

Machine A: 1

Machine B: 2

Machine C: 2

Product Y:

Machine A:2

Machine B: 2

Machine C: 2

Product Z:

Machine A:2

Machine B: 1

Machine C:4

The machines are available for 200, 525 and 350 hours each month. How many units of each product can be manufactured per month if all three machines are utilized to their full capacity?

- Some other Opinion ? - trig -
**Reiny**, Monday, July 11, 2011 at 4:05pmI saw this same question yesterday , tried it and got nowhere.

The way I see it :

for machine A : x + 2y + 2z = 200

for machine B : 2x + 2y + z = 525

for machine C : 2x + 2y + 4z = 350

solving these I got

x = 266 1/3

y = 25

z = -58 1/3

these answers satisfy the above equations, but of course make no sense.... (can't produce negative number of products)

Perhaps somebody else could look at this and see an error in my thinking.

Or ...., the problem could be flawed.

- math- im really confused! please help!! -
**bobpursley**, Monday, July 11, 2011 at 4:43pmThe problem makes no sense. With constraints (machine time), and costs (time on each machine for each product), this would make sense if there was a profit function, which there is not.

- math- im really confused! please help!! -
**Damon**, Monday, July 11, 2011 at 5:38pmThis is an incomplete linear programming problem I suspect.

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