Homework Help: math

Posted by sabrina on Monday, July 11, 2011 at 2:05pm.

A model rocket is launched with an initial velocity of 250 ft/s. The height, h, in feet, of the rocket t seconds after the launch is given by
h = −16t2 + 250t.
How many seconds after launch will the rocket be 730 ft above the ground? Round to the nearest hundredth of a second.

math - bobpursley, Monday, July 11, 2011 at 2:36pm
730=-16t^2+250t

16t^2-250t+730=0

Using the quadratic equation...

t= (250+-sqrt (250^2-4*16*730))/32

solve for t

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