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September 16, 2014

September 16, 2014

Posted by **sabrina** on Monday, July 11, 2011 at 2:05pm.

h = −16t2 + 250t.

How many seconds after launch will the rocket be 730 ft above the ground? Round to the nearest hundredth of a second.

- math -
**bobpursley**, Monday, July 11, 2011 at 2:36pm730=-16t^2+250t

16t^2-250t+730=0

Using the quadratic equation...

t= (250+-sqrt (250^2-4*16*730))/32

solve for t

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