Posted by **sabrina** on Monday, July 11, 2011 at 2:05pm.

A model rocket is launched with an initial velocity of 250 ft/s. The height, h, in feet, of the rocket t seconds after the launch is given by

h = −16t2 + 250t.

How many seconds after launch will the rocket be 730 ft above the ground? Round to the nearest hundredth of a second.

## Answer This Question

## Related Questions

- math - A model rocket is launched with an initial velocity of 250 ft/s. The ...
- math - A model rocket is launched with an initial velocity of 160 ft/s. The ...
- algebra - A model rocket is launched upward with an initial velocity of 200 feet...
- Algebra: Quadratic Functions - A model rocket is launched with an initial ...
- college algebra - A model rocket is launches upward with an initial velocity of ...
- math - A rocket is launch from the top of an 40 foot cliff with an initial ...
- Math - A rocket is launched from the top of a 50 foot cliff with an initial ...
- Math - A model rocket is launched with an initial velocity of 164ft/sec. It's ...
- Math - A model rocket is launched with an initial velocity of 212ft/sec. It's ...
- Math - A model rocket is launched vertically upward so that its height (measured...

More Related Questions