Tuesday

March 31, 2015

March 31, 2015

Posted by **Anonymous** on Monday, July 11, 2011 at 11:01am.

N of AIDS cases in thousands can be approximated by

, where corresponds to

the year 1993.

N= -2x^2+ 76x + 430 x=0

- algebra -
**Henry**, Tuesday, July 12, 2011 at 9:15pmN = -2x^2 + 76x + 430 = 0.

Solve, using the Quad. Formula and get:

x = 43, and -5.

Select + value of x:

x = 43,000 cases.

**Answer this Question**

**Related Questions**

math - AIDS Cases From 1993 to 2003 the cumulative number N of AIDS cases in ...

Algrebra - Please advise on the following: From 1993 to 2003 the cumulative ...

trig - N 5 22x2 1 76x 1 430 Use the equation to find N for each year in the ...

Algebra - The cumulative number of AIDS cases C in the United States from 1982...

MATH - The cumulative number of car accidents from 2000 to 2010 can be modeled ...

MATH - The cumulative number of car accidents from 2000 to 2010 can be modeled ...

math - A sum of money,X was deposited in a saving account at 10 percent ...

math - A sum of money,X was deposited in a saving account at 10 percent ...

Algebra - In 1993, the life expectancy of males in certain countires was 62.3. ...

math - In 1993, the life expectancy of males in a certain country was 61.3 years...