Posted by **cindy** on Sunday, July 10, 2011 at 11:17pm.

I found the equation which was the pythagoras theorem and then took the derivative of the equation but not sure what to plug in where. Oh and I found C(t) to be 743.30

An airplane passes over an airport at noon traveling 500 mi/hr due

West. At 1:00 pm, another airplane passes over the same airport at the same

elevation traveling due North at 550 mi/hr. Assuming both planes maintain their

(equal) elevations, how fast is the distance between them changing at 2:30 pm?

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