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December 20, 2014

December 20, 2014

Posted by **sharron** on Saturday, July 9, 2011 at 9:33pm.

{-----------

74y^3

- algebra -
**bobpursley**, Saturday, July 9, 2011 at 10:40pmI dont understand your 74y^3? If that is your answer, it is wrong.

see the beginning negative sign

see the 37, that is not 73

where is the 1/x ?

(y^-2)^-2=y^4

- algebra -
**swirl**, Sunday, July 10, 2011 at 2:30pmshort answer.raise the quanity in parentheses to the indicated exponent, and simplify the resulting expression. express answers with positive exponents.

{-37x^-1y^-2}^-2 }

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{ 74y^3 }

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