Posted by sharron on Saturday, July 9, 2011 at 9:29pm.
10x^3y^3
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40x^-3y^-4
Use the law of negative exponents:
1/a^x = a^(-x)
10x^3y^3
--------
40x^-3y^-4
=(10/40) x^3y^3 * x^-(-3)y^-(-4)
=(1/4) x^3*x^3 * y^3*y^4
=(1/4)x^6 y^7
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