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March 27, 2015

March 27, 2015

Posted by **sharron** on Saturday, July 9, 2011 at 9:29pm.

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40x^-3y^-4

- algebra -
**MathMate**, Sunday, July 10, 2011 at 7:28am10x^3y^3

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40x^-3y^-4

Use the law of negative exponents:

1/a^x = a^(-x)

10x^3y^3

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40x^-3y^-4

=(10/40) x^3y^3 * x^-(-3)y^-(-4)

=(1/4) x^3*x^3 * y^3*y^4

=(1/4)x^6 y^7

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