Wednesday

January 28, 2015

January 28, 2015

Posted by **George** on Friday, July 8, 2011 at 4:03pm.

while abs(x(k)/x(k-1) – x(k-1)/x(k-2))>0.001

I think I'm doing something wrong... Here's my attempt at a solution

a=input('Please enter the first two numbers of the Fibonacci sequence in "[# #]" form. Do not enter [0 1] or [1 1]. Your free to enter anything else though.');

x=[a ones(1,100000)];

z=3;

while abs(x(z)/x(z-1)-x(z-1)/x(z-2))>0.001

x(z)=x(z-2)+x(z-1);

z=z+1;

end

g=x(find(x>1));

**Answer this Question**

**Related Questions**

Computer Science - MATLAB - I guess it was skipped One interesting property of a...

maths! please help me it is an emergency!!!!!!!!!! - what is the fibonacci ...

Math (fibonacci - A sequence of numbers is called a Fibonacci-type sequence if ...

math - The Fibonacci sequence of numbers begins 1,1,2,3,5,8,13,21,34,55,…and ...

Fibonacci sequence - The Fibonacci sequence a1=1,a2=1,a3=2,a4=3,a5=5,a6=8… is ...

Math - F25= 75,025 and F26= 121,393 where Fn is the nth term in the Fibonacci ...

Pre-Calc - Find three examples of the Fibonacci sequence in nature. Write a ...

Math - Hello, I can't find a pattern to answer this question, can you help? The ...

maths - The common ratio r of a geometric sequence satisfies the quadratic ...

Math - A sequence is formed by adding together the corresponding terms of a ...