posted by Chemistry on .
How many milliliters of 0.355 M NaF solution are needed to react completely with 24.6 mL of 0.216 M CaCl2 solution? How many grams of CaF2 will be formed? The reaction is
CaCl2(aq) + 2NaF(aq) → CaF2(s) + 2NaCl(aq)
According to your balanced equation, each mole of CaCl2 needs one mole of NaF.
Moles of CaCl2: .0246*.216
volume of NaF=that/.355 in liters.