v=2(ab+bc+ca), solve for a

Please look back at your previous post before posting the same question again.

http://www.jiskha.com/display.cgi?id=1310130604

sorry, it's a different question. That one was miswritten. I accidently wrote cd instead of ca.

To solve for "a" in the equation v = 2(ab + bc + ca), we need to isolate the variable "a" on one side of the equation. Here's how we can do that:

Step 1: Distribute the 2 to each term inside the parentheses:
v = 2ab + 2bc + 2ca

Step 2: Group the terms containing "a" together:
v = 2ab + 2ca + 2bc

Step 3: Factor out "a" from the terms that contain it:
v = 2a(b + c) + 2bc

Step 4: Re-arrange the equation to isolate the "a" term:
v - 2bc = 2a(b + c)

Step 5: Divide both sides of the equation by 2 times (b + c):
(v - 2bc) / (2(b + c)) = a

So, the solution for "a" is (v - 2bc) / (2(b + c)).