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July 22, 2014

July 22, 2014

Posted by **Megan** on Friday, July 8, 2011 at 10:02am.

--any help would be very appreciated--

- calculus -
**Reiny**, Friday, July 8, 2011 at 10:39amlet the base by x by x and the height y

(make a sketch)

surface area = x^2 + 4xy

x^2 + 4xy = 60

y = (60- x^2)/(4x)

volume= x^2(y) = x^2(60-x^2)/(4x)

= 15x - (1/4)x^3

d(volume)/dx = 15 - (3/4)x^2

= 0 for a max of volume

(3/4)x^2 = 15

x^2 = 20

x = √20

so max volume = 15√20 - (1/4)20√20 = 10√20 or 20√5

- calculus -
**Reiny**, Friday, July 8, 2011 at 11:00amlet the base by x by x and the height y

(make a sketch)

surface area = x^2 + 4xy

x^2 + 4xy = 60

y = (60- x^2)/(4x)

volume= x^2(y) = x^2(60-x^2)/(4x)

= 15x - (1/4)x^3

d(volume)/dx = 15 - (3/4)x^2

= 0 for a max of volume

(3/4)x^2 = 15

x^2 = 20

x = √20

so max volume = 15√20 - (1/4)20√20 = 10√20 or 20√5

- calculus -
**Megan**, Friday, July 8, 2011 at 11:33amthank you very much

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