a force of 4 N acts on a body of mass 2 kg for 4 sec . assuming the body to be initialy at rest . find the distance covered in 10sec after force start acting
d=1/2 a t^2
but a=force/mass
solve so find d for the first 4 seconds, while the object is accelerating.
Then find its velocity at that time..
vf=at
so you now have the distance and velocity after 4 seconds.
The next six seconds, it travels at this velocity d=v*6
add the two distances together.
64m
To find the distance covered by the body, we need to first calculate the acceleration using Newton's second law of motion:
F = m * a
Here, F is the force, m is the mass, and a is the acceleration.
Given:
Force (F) = 4 N
Mass (m) = 2 kg
From the equation, let's solve for acceleration (a):
a = F / m
Substituting the values, we get:
a = 4 N / 2 kg
a = 2 m/s^2
Now, we can use the equations of motion to calculate the distance covered in 10 seconds. Since the body was initially at rest, we can use the equation:
s = ut + (1/2) * a * t^2
Where:
s is the distance covered
u is the initial velocity (which is zero in this case)
t is the time (10 seconds)
Plugging in the values, we get:
s = 0 + (1/2) * 2 m/s^2 * (10 s)^2
s = 0 + (1/2) * 2 m/s^2 * 100 s^2
s = 0 + 200 m
s = 200 meters
Therefore, the body will cover a distance of 200 meters in 10 seconds.