v=2(ab+bc+cd) for a
v = 2ab + 2bc + 2cd
v - 2bc - 2cd = 2ab
a = (v-2bc-2cd)/(2b)
post it.
To solve for a in the equation v=2(ab+bc+cd), we need to isolate a on one side of the equation. Let's go through the steps:
Step 1: Distribute 2 to the terms inside the parentheses.
v = 2ab + 2bc + 2cd
Step 2: Group the terms involving a.
v = 2ab + (2bc + 2cd)
Step 3: Combine like terms.
v = 2ab + 2(bc + cd)
Step 4: Move the terms not involving a to the other side of the equation.
v - 2(bc + cd) = 2ab
Step 5: Divide both sides by 2b.
(v - 2(bc + cd))/(2b) = a
So, the final solution for a is:
a = (v - 2(bc + cd))/(2b)