Posted by **neeha** on Friday, July 8, 2011 at 2:00am.

A manufacturer produces three types of radios: deluxe, standard and economy. Each radio uses three different types of transistors: P, Q and R. The deluxe radio uses 2 P's, 7 Q's and 1 R. The standard contains 2 P's, 3 Q's and 1 R, and the economy model requires 1 P, 2 Q's and 2 R's.

How many radios of each type can be constructed if the total number of transistors (P's, Q's and R's) available are 2200, 3400 and 1400 respectively and all transistors must be used?

- System of Linear Equations -
**Reiny**, Friday, July 8, 2011 at 9:27am
number of deluxe : x

number of standard : y

number of econony : z

your system is

2x + 2y + z = 2200

7x + 3y + 2z = 3400

x + y + 2z = 1400

2nd - 3rd : 6x + 2y = 2000 or ---> 3x + y = 1000

double the 1st, subtract the 3rd

3x+3y=3000

subtract the x,y equations:

2y = 2000

y = 1000

sub into 3x+y=1000

3x + 1000= 1000

3x=0

x=0 , !!!!!????

Unless I made some arithmetic error, I think your data is flawed.

- System of Linear Equations -
**MathMate**, Monday, July 11, 2011 at 2:35pm
I get the same results, x is indeed zero.

See:

http://www.jiskha.com/display.cgi?id=1310358660

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