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November 27, 2014

November 27, 2014

Posted by **Jenna** on Thursday, July 7, 2011 at 6:25pm.

A = {l, a, t, e, r}, B = {l, a, t, e},

C = {t, a, l, e}, D = {e, a, t}

- Question incomplete :( -
**MathMate**, Thursday, July 7, 2011 at 10:50pmThe question does not appear complete. Please check.

- Geometry-help please :( -
**Jen**, Thursday, July 7, 2011 at 11:46pmSorry about that....

Given the following sets, select the statement below that is true.

A = {l, a, t, e, r}, B = {l, a, t, e}, C = {t, a, l, e}, D = {e, a, t}

B ⊂ C and C ⊆ A

C ⊆ B and D ⊂ B

D ⊂ A and A ⊂ D

B ⊂ A and C ⊂ D

D ⊆ A and A ⊂ C

- Geometry-help please :( -
**MathMate**, Friday, July 8, 2011 at 6:03pm⊂ means "a proper subset of"

P ⊂ Q requires that every element of P is also in element Q, and in addition, P cannot be equal to Q.

⊆ means "a subset of, or equal to"

Based on the given information, give an attempt at the solution.

- Geometry-help please :( -
**Jen**, Saturday, July 9, 2011 at 9:32pmmy answer would be C ⊆ B and D ⊂ B...is that correct?

- Geometry-help please :( -
**MathMate**, Saturday, July 9, 2011 at 10:14pmYour answer is correct.

C={t,a,l,e}

B={l,a,t,e}

Since they contain exactly the same elements, we cannot say C⊂B, nor B⊂C, but C⊆B or B⊆C would both be correct.

Also, since

D = {e, a, t}

every element of D is in C, while the element "l" that is in C but not n D.

We can therefore safely say that D is a proper subset of C.

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