Posted by **Kate** on Thursday, July 7, 2011 at 6:18pm.

A 5.0 m diameter merry-go-round is initially turning with a 4.6 s period. What is the speed of a child on the rim?

- physics -
**Lauren**, Wednesday, September 26, 2012 at 9:39pm
T = (2pir)/v with T being the period, r being the radius, and v being the speed. Don't forget that radius is half the diameter.

So, v*4.6s = 2*pi*2.5m

## Answer this Question

## Related Questions

- College Physics - A 2.0 m diameter merry-go-round is initially turning with a 4....
- physics - A 4.1-m-diameter merry-go-round is initially turning with a 4.2 period...
- Physics - In a playground, there is a small merry-go-round of radius 1.20 m and ...
- Physics - In a playground, there is a small merry-go-round of radius 1.20 m and ...
- Physics - In a playground, there is a small merry-go-round of radius 1.20 m and ...
- Physics - A 5.2-m-diameter merry-go-round is initially turning with a 3.0s ...
- physics 23 - A 4.1-m-diameter merry-go-round is initially turning with a 4.2 ...
- physics - A playground merry-go-round has a radius 2.6 m and a rotational ...
- physics - A 39.0kg child runs with a speed of 2.70m/s tangential to the rim of a...
- physics - A merry go round in the park has a radius of 1.8 m and a rotational ...

More Related Questions