Post a New Question


posted by .

A 5.0 m diameter merry-go-round is initially turning with a 4.6 s period. What is the speed of a child on the rim?

  • physics -

    T = (2pir)/v with T being the period, r being the radius, and v being the speed. Don't forget that radius is half the diameter.

    So, v*4.6s = 2*pi*2.5m

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question