Homework Help: chemistry

Posted by Carol on Thursday, July 7, 2011 at 1:33pm.

a 30.0 ml solution of potassium nitrate was diluted to 125 ml and 25 ml of this solution were then diluted to 150 ml. the concentration of the final solution is 0.00307 M. Calculate the concentration of the original solution.

chemistry - DrBob222, Thursday, July 7, 2011 at 2:50pm
xM*(30/125)*(25/150) = 0.00307
chemistry - Sarah (C), Thursday, July 7, 2011 at 2:53pm
i do not know if this is right but this is how i would do it.

M1V 1=M2V2.

(0.00307 M) X (150ml)= (M2) X (30 ml)

and then you solve to get m2
chemistry - DrBob222, Thursday, July 7, 2011 at 3:04pm
Sarah's method will work if you do it TWICE; once for each dilution.
0.00307*150 = 25*c
c = ??
??*125 = 30c
c = xx.
You should arrive at the same answer either way.

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