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April 19, 2015

Posted by **Steff** on Thursday, July 7, 2011 at 11:35am.

∫((e^-x-1)/(e^-x + x)^2) dx

I am trying to use the substitution method.

u=e^-x + x

du= -e^-x+1 dx

Right so far?

- integration (calculus) -
**Steff**, Thursday, July 7, 2011 at 11:45amgot it figured out.

- integration (calculus) -
**Bosnian**, Thursday, July 7, 2011 at 1:16pmGo to:

wolframalpha dot com

When page be open in rectangle type:

integrate ((e^-x-1)/(e^-x + x)^2) dx

and click option =

When you see solution click option:

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