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integration (calculus)

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Find the indefinite integral.

∫((e^-x-1)/(e^-x + x)^2) dx

I am trying to use the substitution method.

u=e^-x + x
du= -e^-x+1 dx

Right so far?

  • integration (calculus) -

    got it figured out.

  • integration (calculus) -

    Go to:
    wolframalpha dot com

    When page be open in rectangle type:

    integrate ((e^-x-1)/(e^-x + x)^2) dx
    and click option =

    When you see solution click option:

    Indefinite integral:Show steps

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