# integration (calculus)

posted by
**Steff**
.

Find the indefinite integral.

∫((e^-x-1)/(e^-x + x)^2) dx

I am trying to use the substitution method.

u=e^-x + x

du= -e^-x+1 dx

Right so far?

posted by
**Steff**
.

Find the indefinite integral.

∫((e^-x-1)/(e^-x + x)^2) dx

I am trying to use the substitution method.

u=e^-x + x

du= -e^-x+1 dx

Right so far?