algebra system of equation
posted by eric on .
10x5y=20
7x5y=26

Eq1: 10x5y = 20.
Eq2: 7x5y = 26.
Multiply Eq1 by 1:
10x+5y = 20,
+7x5y = 26.
Sum:x = 3x+0 = 46,
x = 46/3 = 15 1/3.
In Eq2, substitute 46/3 for x:
7(46/3)  5y = 26,
Solve for y and get:
26 2/3 = 80/3.
Solution Set = (x,y) = (15 1/3,26 2/3).
Check the given Eqs and make sure the signs are correct.