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July 23, 2014

July 23, 2014

Posted by **CC** on Wednesday, July 6, 2011 at 10:45pm.

h(x)=(7x˛-8x-5)/(8x˛-3x+9)

g(x)=(x˛+4x-8)/(x-8)

- Algebra II -
**Reiny**, Wednesday, July 6, 2011 at 11:04pmdivide top and bottom by x^2 to get

h(x) = (7 - 8/x - 5/x^2)/(8 - 3/x + 9/x^2)

as x approaches infinity, h(x) --> 7/8

so the horizontal axis is y = 7/8

the second one does not have a horizontal axis, but ...

g(x) = x + 12 + 88/(x-8)

there is an oblique asymptote at y = x + 12

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