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April 20, 2014

Posted by **renee** on Wednesday, July 6, 2011 at 7:36pm.

ƪxe^2x dx

- Cal -
**SraJMcGin**, Wednesday, July 6, 2011 at 7:48pmPlease see your next post as there is the same problem.

Look at Related Questions below for they look similar?

Sra

- Cal -
**Reiny**, Wednesday, July 6, 2011 at 8:24pmlet u = x

du/dx = 1

du = dx

let dv = e^(2x)dx

dv/dx = e^(2x)

v = (1/2)e^(2x)

formula:

[int] u dv = uv - [int] v du

[int] x e^(2x) dx = (x)(1/2)e^(2x) - [int] (1/2)e^(2x) dx

= (1/2)xe^(2x) - (1/4)e^(2x)

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