What pressure (atm) is exerted by a column of ethanol 86.0 cm high. The density of ethanol is 0.789 g/cm3 and 9.8 m/s2 as your gravitational constant.

pressure = density*acceleration gravity*height.

0.789g/cc x 86 cm x 980 cm/s^2 =?? Pa. Divide by 1000 to convert to kPa and divide by 101.325 to convert to atm.
Read here.
http://hyperphysics.phy-astr.gsu.edu/hbase/pflu.html#fpc

To find the pressure exerted by a column of ethanol, you need to use the equation:

Pressure = Density * Gravitational constant * Height

First, let's convert the height from centimeters to meters:

86.0 cm = 0.86 m

Next, we can substitute the given values into the equation:

Pressure = 0.789 g/cm^3 * 9.8 m/s^2 * 0.86 m

To ensure consistent units, let's convert the density from grams per cubic centimeter to kilograms per cubic meter:

0.789 g/cm^3 = 789 kg/m^3 (since 1 g/cm^3 = 1000 kg/m^3)

Now we can calculate the pressure:

Pressure = 789 kg/m^3 * 9.8 m/s^2 * 0.86 m

Using a calculator, we find:

Pressure ≈ 6719.432 Pa

Since 1 atm = 101325 Pa, we can convert to atm:

Pressure ≈ 6719.432 Pa / 101325 Pa

Pressure ≈ 0.0662 atm

Therefore, the pressure exerted by the column of ethanol is approximately 0.0662 atm.