Post a New Question

Math(Pre=Calc)

posted by on .

The first term in a sequence of number is t1 = 4. The terms that follow are defined by the formula: tn - tn-1 = 3n -2. Determine the value of t50.

  • Math(Pre=Calc) - ,

    so
    t2 = t(1) + 3(2) - 2 = 4 + 4 = 8
    t3 = t2 + 3(3)-2 = 8 + 7 = 15
    t4 = t3 + 3(4) - 2 = 15+10=25
    t5 = t4 + 3(5) - 2 = 25+13 = 38

    so the sequence is
    4 8 15 25 38 ...
    first differences: 4 7 10 13 ....
    second diff : 3 3 3 3 ...

    ahhh, so the expression is quadratic.

    see if can come up with a quadratic to express the sequence 4 8 15 25 38 ....

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question