What pressure (atm) is exerted by a column of ethanol 86.0 cm high. The density of ethanol is 0.789 g/cm3 and 9.8 m/s2 as your gravitational constant.
To find the pressure exerted by a column of ethanol, we can use the formula:
Pressure = Density × Gravity × Height
Given:
Height (h) = 86.0 cm = 0.86 m
Density (ρ) = 0.789 g/cm^3 = 789 kg/m^3
Gravity (g) = 9.8 m/s^2
Now we can plug these values into the formula to calculate the pressure:
Pressure = 789 kg/m^3 × 9.8 m/s^2 × 0.86 m
First, convert the units of density to match the units of gravity and height:
Density = 789 kg/m^3
Now, substitute the values into the formula:
Pressure = 789 kg/m^3 × 9.8 m/s^2 × 0.86 m
Calculating the multiplication:
Pressure = 6587.892 kg·m·s^(-2) = 6587.892 N/m^2
Finally, convert the pressure from N/m^2 to atm:
1 atm = 101325 N/m^2
Pressure (in atm) = 6587.892 N/m^2 / 101325 N/m^2
Therefore, the pressure exerted by the column of ethanol is approximately 0.065 atm.