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December 18, 2014

December 18, 2014

Posted by **Allen** on Sunday, July 3, 2011 at 6:46pm.

- mathematics -
**Henry**, Tuesday, July 5, 2011 at 5:10pm(2a^2-3a-2)/(4a^2-1) Divided by

(a^2-4)/(2a^2-5a+2)

Invert divisor(2nd fraction) and multiply:

(2a^2-3a-2)/(4a^2-1)*(2a^2-5a+2)/a^2-4.

(a-2)(2a+1)/(2a+1)(2a-1)*(a-2)(2a-1)/

(a+2)(a-2) = (a-2)/(a+2).

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