An aluminum cube that has an edge length of 7 cm. is placed in a beaker of water that is filled to the brim. As a result the water overflows. what volume of water overflows when the aluminum cube is submerged in the water?
the aluminum displaces its own volume of water when it sinks (it does not float)
Volume = 7*7*7 = 343 cm^3
To calculate the volume of water that overflows when the aluminum cube is submerged, we need to determine the volume of the cube and compare it to the volume of the beaker.
The volume of a cube is calculated by cubing the length of its edge. In this case, the edge length of the cube is given as 7 cm. Therefore, the volume of the cube can be calculated as follows:
Volume of cube = (Edge length)^3
Volume of cube = 7 cm * 7 cm * 7 cm
Volume of cube = 343 cm^3
Next, we need to determine the volume of the beaker. The beaker is completely filled to the brim with water. Hence, the volume of the water is equal to the volume of the beaker.
To find the volume of the beaker, we can use a measuring cylinder or a graduated cylinder to measure the amount of water that overflows when the cube is submerged. This will give us the volume of the water that spilled, which is equal to the volume of the cube.
Therefore, the volume of water that overflows when the aluminum cube is submerged in the beaker is 343 cm^3.