Posted by **Shelly** on Sunday, July 3, 2011 at 3:46pm.

write a quadratic equation in the variable x having the given numbers as solution. Type the equation in standard form, ax^2+bx+c=0

solution 4, only solution

- Algebra 2 -
**Damon**, Sunday, July 3, 2011 at 3:50pm
You left out the numbers

assume p and q

then

(x-p)(x-q) = 0

multiply it out

- Algebra 2 -
**Shelly**, Sunday, July 3, 2011 at 3:52pm
no numbers left out

- Algebra 2 -
**Damon**, Sunday, July 3, 2011 at 3:53pm
So what were the given numbers?

- Algebra 2 -
**Damon**, Sunday, July 3, 2011 at 3:54pm
Oh, you mean the number 4 is the solution? Then 4 and 4

(x-4)(x-4) = 0

x^2 - 8 x + 16 = 0

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