posted by jenna .
find the perimeter and area of a right triangle if the shortest side is 20 mm. and the longest side is 52 mm. include correct units with each part in solution.
Now I did one very similar to this for you a couple of hours ago. You try.
i think P = a + b + c right?
and A = 1/2bh right?
yes and c = 52 = sqrt (a^2+b^2)
(because the longest side is the hypotenuse, not one of the legs)
im still a little confused with this problem....
i don't think im getting this problem...would it be 20 * 52 = 1040 mm?
PLEASE ASSIST :(