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Posted by on Sunday, July 3, 2011 at 10:18am.

a car moving on a straight road with a speed of 20m/s. at t=0 the driver of the car applies the breaks after watching an obstacle 150m ahead. after application of breaks, the car retards with 2m/s^2. find the position of the car from the obstacle at t=15s.

  • physics - , Sunday, July 3, 2011 at 10:54am

    d = 20(15) -(1/2)(2)(15^2)
    = 300 - 225 = 75 m
    150 - 75 = 75

  • physics - , Monday, July 4, 2011 at 6:37pm

    Post it.

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