Posted by alexa on Saturday, July 2, 2011 at 1:38pm.
the velocity is constant so there is no net force on the entire train.
There is however a force back on the engine from the drag of all the cars. It is equal to the thrust from the engine wheels
It is biggest between the engine and the first car, being the sum of drags from all the cars behind
HOWEVER!!!
since each car moves at constant velocity, the NET force on each car is zero.
As the net drag decreases moving back on the train, the net thrust also decreases by the same amount.
so
A
F1 = F2
Related Questions
dynamics, check my ans - Three identical train locomotives, on separate tracks, ...
physics - An engineer of a passenger train traveling at 25.0 m/s sights a ...
Physics - the engineer of a passenger train traveling at 25.0 m/s sights a ...
physics - The engineer of a passenger train traveling at 25.0 m/s sights a ...
physics - A passenger train is traveling at 30 m/s when the engineer sees a ...
physics - A train consists of 40 freight cars, each having a mass of 2.71 &...
physics - A toy car is given a quick push so that it moves on an inclined ramp. ...
physics - Hi I need help to figure out if these situations are possible or ...
Physics - A freight train traveling with a velocity of -4.0 m/s begins backing ...
Physics - A train engine pulls out of a station along a straight horizontal ...
For Further Reading
