Questions LLC
Login
or
Sign Up
Ask a New Question
Science
Physics
The two ends of a train moving with a constant acceleration pass a certain point with velocities u and v.what is the velocity with which the middle point of the train passes the same point?
1 answer
What is (U+v)/2 ?
You can
ask a new question
or
answer this question
.
Similar Questions
two ends of a train moving with constant acceleration pass a certain point with velocities u and v. what is the velocity with
Top answer:
I agree with mam. What you are figuring is the rms velocity. Here is why: velocity u is front, then
Read more.
A passenger on a train traveling 90km/h on a straight, level track notes that it takes another train (180 m long and moving with
Top answer:
The relative velocity is the distance divided by the time. Now subtract the train moving 90km/hr,
Read more.
a train slows down from 104m/s to 76m/s with constant decceleration in 440m. 1) what is the acceleration of the train? 2) how
Top answer:
Vf^2=Vi^2+2ad solve for a then 2) vf=vi+at solve for t.
Read more.
A subway train starting from rest leaves a station with a constant acceleration. At the end of 5.24 s, it is moving at 13.4144
Top answer:
To find the train's displacement in the first 3.42696 seconds of motion, we can use the kinematic
Read more.
A subway train starting from rest leaves a station with a constant acceleration. At the end of 5.24 s, it is moving at 13.4144
Top answer:
v = at 13.4144 = 5.24a a = 2.56 s = 1/2 at^2 s = .5 * 2.56 * 3.42696^2 s = 15.032390197 since you
Read more.
A train starts from rest and then accelerates at a constant acceleration of 1.4ms-2 for 10s. The train then moves with a
Top answer:
Graph velocity vs time. That area below the graph is the distance covered. You can easily determine
Read more.
A subway train starting from rest leaves a
station with a constant acceleration. At the end of 5.59 s, it is moving at 11.5154
Top answer:
Well, let me calculate that for you using my trusty clown calculator. Given that the train starts
Read more.
A subway train starting from rest leaves a station with a constant acceleration. At the end of 7.94s, it is moving at
Top answer:
To find the train's displacement in the first 5.57388 seconds of motion, we can use the equation for
Read more.
A train with a mass 5x10^5 kg is moving with a speed 80km/hr. If the train stops in 2min...1)What is the acceleration of the
Top answer:
1. Vo = 80km/h = 80000m/3600s=22.2 m/s. V = Vo + a*t. a=(V-Vo)/t = (0-22.2)/120s=-0.185 m/s^2. 2. F
Read more.
A railroad flatcar is loaded with crates. The coefficient of static friction between the crates and the floor is 0.27. If the
Top answer:
Max friction force = M g u The equals M a when it is on the verge of slipping. Therefore a = u g is
Read more.
Related Questions
If an object is moving at a constant velocity, which must be true?(1 point)
Its acceleration is increasing. Its acceleration is a
A train is moving past a crossing where cars are waiting for it to pass. While waiting, the driver of the lead car becomes
A train is moving along a straight horizontal track. A pendulum suspended from the roof of one of the carriages of train is
A train moving at a constant speed on a surface inclined upward at 10.0° with the horizontal travels a distance of 400 meters
the speed of the train is reduce uniformly from 15m/s to 7m/s while travelling a distance of 90m.
a) compute the acceleration b)
A train is moving parallel and adjacent to a highway with a constant speed of 22 m/s. Ini- tially a car is 35 m behind the
Newton's Second Law Quick Check4 of 44 of 4 ItemsQuestionWhich situation describes a negative acceleration?(1 point)Responsesa
A railroad flatcar is loaded with crates. The coefficient of static friction between the crates and the floor is 0.27. If the
A railroad flatcar is loaded with crates. The coefficient of static friction between the crates and the floor is 0.27. If the
A railroad flatcar is loaded with crates. The coefficient of static friction between the crates and the floor is 0.27. If the
