Posted by **Violet ** on Thursday, June 30, 2011 at 11:11pm.

A chemist does a reaction rate analysis on the following reaction:

2CO (g) + O2 (g) → 2CO2 (g)

She collects the following data:

Trial Initial Concentration of

CO (M) Initial Concentration

of O2 (M) Instantaneous

Reaction Rate (M/s)

1 0.150 0.150 0.113

2 0.300 0.150 0.226

3 0.300 0.300 0.904

What is the rate equation for this reaction?

- Chemistry -
**DrBob222**, Friday, July 1, 2011 at 6:20pm
The rate equation is rate = k(CO)^x(O2)^y.

Divide rate 2 by rate 1.

0.226/0.113 = 2 and

2 = (0.300)^{x}(0.150)^{y}/(0.150)^{x}(0.150)^{y}

Note that 0.150^{y} cancels with 0.150^{y} and leaves just

2= (2)^{x} and x must be 1.

Do the same thing for rate 3 divided by rate 2 and determine y. You should get 2. Then substitute x = 1 and y = 2 into any of the three rate equations to determine k, then write the equation. If you get stuck, post your work in a new post at the top of the page (this post is close to the bottom when I read it) and I can help you through it.

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