Posted by Violet on .
A chemist does a reaction rate analysis on the following reaction:
2CO (g) + O2 (g) → 2CO2 (g)
She collects the following data:
Trial Initial Concentration of
CO (M) Initial Concentration
of O2 (M) Instantaneous
Reaction Rate (M/s)
1 0.150 0.150 0.113
2 0.300 0.150 0.226
3 0.300 0.300 0.904
What is the rate equation for this reaction?

Chemistry 
DrBob222,
The rate equation is rate = k(CO)^x(O2)^y.
Divide rate 2 by rate 1.
0.226/0.113 = 2 and
2 = (0.300)^{x}(0.150)^{y}/(0.150)^{x}(0.150)^{y}
Note that 0.150^{y} cancels with 0.150^{y} and leaves just
2= (2)^{x} and x must be 1.
Do the same thing for rate 3 divided by rate 2 and determine y. You should get 2. Then substitute x = 1 and y = 2 into any of the three rate equations to determine k, then write the equation. If you get stuck, post your work in a new post at the top of the page (this post is close to the bottom when I read it) and I can help you through it.