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Physics-Math

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Suppose that a car starts from rest at position -3.31m and accelerates with a constant acceleration of 4.15m/s^2. At what time t is the velocity of the car 19.2m/s?

  • Physics-Math -

    v=u+at
    19.2=0+4.15t
    t=19/4.15
    t=4.8
    check the answer

  • Physics-Math -

    What is the "u" variable standing for?

  • Physics-Math -

    Your answer's wrong, btw, sorry :(

  • Physics-Math -

    u is the initial velocity that is 0 as it as rest ..
    whats the answer ?

  • Physics-Math -

    Thread necro... but I wanted to make sure that anyone seeing this can correctly divide 19.2/4.15 = 4.626506024

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