Friday
May 29, 2015

Homework Help: Chemistry

Posted by Brayden--help Dr. Bob on Thursday, June 30, 2011 at 1:32pm.

If you have 200 ml of a 0.1M solution of acetic acid (pka=4.75),
1. How many ml of a solution of 1.O M NaOH would you need to adjust the pH to 5.2?


"Chemistry - DrBob222, Wednesday, June 29, 2011 at 8:41pm
200 mL x 0.1M = 20 mmoles.
1.
............HAc + OH^- ==> Ac^- H2O
initial.....20.0...0........0
added..............x...........
change.......-x....-x........+x
equil......20-x.....0.........+x
Substitute into the Henderson-Hasselbalch equation and solve for x which will be mmoles NaOH. You can take it from there."


So I have substituted for hernderson hasselbalch

5.2= 4.75 + {log [x]/[20 mmoles]

1.75= log [x]/20mmoles

10^1.75= [x]/20
56. 234 = x/20
1,124.68 mmoles of NaOH.

Could this be right? Now to convert this to ml to answer the question, would I divided by 1.0M? So I would need 1.124 L ?

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