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October 25, 2014

October 25, 2014

Posted by **marissa** on Thursday, June 30, 2011 at 2:29am.

14a^8y^3-7a^4y^5+28a^12y^2/7a^4y

- algebra -
**Henry**, Friday, July 1, 2011 at 2:31pm(4a^8Y^3 - 7a^4Y^5 + 28a^12Y^2) / 7a^4Y

14a^8Y^3 / 7a^4Y - 7a^4Y^5 / 7a^4Y +

28a^12Y^2 / 7a^4Y.

Divide each numerator by 7a^4Y:

2a^4Y^2 - Y^4 + 4a^8Y,

Factor out Y:

Y(2a^4Y - Y^3 + 4a^8).

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