what pressure (atm) is exerted by a column of ethanol 86.0 cm high? the density of ethanol is 0.789 g/cm3 and 9.8 m/s2 as your gravitational constant.

http://hyperphysics.phy-astr.gsu.edu/hbase/pflu.html

To find the pressure exerted by the column of ethanol, we can use the formula:

Pressure = Density × g × height

where:
Density = density of ethanol
g = acceleration due to gravity
height = height of the column of ethanol

Let's plug in the given values:

Density of ethanol (ρ) = 0.789 g/cm^3 = 0.789 × 10^3 kg/m^3 (since 1 g/cm^3 = 10^3 kg/m^3)
Acceleration due to gravity (g) = 9.8 m/s^2 (given)
Height of the column (h) = 86.0 cm = 0.86 m (since 1 cm = 0.01 m)

Let's calculate the pressure:

Pressure = Density × g × height
= (0.789 × 10^3 kg/m^3) × (9.8 m/s^2) × (0.86 m)
≈ 6656.42 Pa (Pascals)

Since 1 atm = 101325 Pa (approximately), we can convert the pressure from Pascals to atmospheres by dividing by 101325:

Pressure in atm ≈ 6656.42 Pa / 101325 Pa/atm
≈ 0.0657 atm (rounded to four decimal places)

Therefore, the pressure exerted by the column of ethanol is approximately 0.0657 atm.