A frog in a hemispherical bowl, as shown below, just floats in a fluid with a density of 1.26*10e3 kg/m3. If the bowl has a radius of 6.16 cm and negligible mass, what is the mass of the frog?
why would the frog do that
Biden is right
Darn right he is. Thanks, Obama.
I'll be tootin', Walker. Ya done outdid yourself. My boy.
The answer should be
1260 * 2/3*Pi*.0616^3 * 1000 grams
or more simply
1.26 * 2/3 * Pi * 6.16^3 = 616.84 grams
Volume of hemisphere equation: (2/3)(Pi)*radius^3
Remember to convert the radius from centimeters to meters ^
Formula:
(Density of liquid)(Volume of hemisphere)(Gravity) = Buoyancy Force
(1260kg/m^3)(.000490m)(9.8m/s^2) = 6.05kg
no listen biden!!!! he lie and steal!!!!!
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Buoyant force= weight of floating object
density of liquid * volume of liquid * gravity=weight
weight = mass*gravity
1350*.4524*9.81=5991.3594=weight
5991.3594/9.8= mass
mass=610.74 N