Posted by renee on Tuesday, June 28, 2011 at 12:17pm.
Hint:
note the x^4 in parentheses, and that d(x^4)/dx = 4x^3, so substituting
y=x^4 would have a good chance of success.
If
y=x^4-16,
dy=4x^3dx
So
I=∫(X^4-16)^5 X^3 DX
=∫y^5(dy/4)
proceed with the power rule and put back y=x^4-16 into I.
Do not forget the integration constant C.
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