Posted by Cindy on Monday, June 27, 2011 at 9:02pm.
First determine where the equivalence point is (how many mL HNOe are required).
At zero mL, calculate pH from pure Ba(OH)2.
All points from zero to the equivalence point, use an ICE chart to determine how much Ba(OH)2 remains, then determine pH from that. Remember to take into account the dilution of the base.
At equivalence point, the pH is the pH of pure water since this is a strong acid/strong base titration.
All points after the equivalence point, use an ICE chart to determine how much HNO3 is in excess and determine pH from that. Post your work if you get stuck.
Related Questions
Chemistry - A 30 mL sample of 0.150 M KOH is titrated with 0.125 M HClO4 ...
Chemistry - A 30 mL sample of 0.150 M KOH is titrated with 0.125 M HClO4 ...
Chemistry - A 35.0 mL sample of 0.150 M acetic acid is titrated with 0.150 M ...
Chemistry - A 30.00mL sample of 0.150M KOH is titrated with 0.125M HClO4 ...
chem - A 75.0 mL volume of 0.200 M NH3 (Kb=1.8x10^-5) is titrated with 0.500 M ...
chem - A 75.0 mL volume of 0.200 M NH3 (Kb=1.8x10^-5) is titrated with 0.500 M ...
chemistry - a solid sample of impure Ba(OH)2 is added to 400.0 mL of 0.5000 M of...
science - 25 ml sample of 0.150 m solution of aqueous trimethylamine is titrated...
Chemistry - A 100.0 mL sample of 0.100 M formic acid, CHOOH, is titrated with 0....
chemistry - Consider the titration of 88.0 mL of 0.150 M Ba(OH)2 by 0.600 M HCl...
For Further Reading