Homework Help: Calculus

Posted by Mea on Monday, June 27, 2011 at 8:30pm.

An investment grows ar a rate of 2.5% each year compounded continuously. Approximately how long will it take the investment to double?

Calculus - Damon, Monday, June 27, 2011 at 8:36pm
dx/dt = .025 x
dx/x = .025 dt

ln x = .025 t + c

x = e^(.025 t+c) = e^c e^.025 t

so x = C e^.025 t
at t= 0, x = C e^0 = C
when is x = 2C ???
2C = C e^.025 x
e^.025 x = 2
.025 x = ln 2 = .6931
x = 27.7 years

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