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February 1, 2015

February 1, 2015

Posted by **Mea** on Monday, June 27, 2011 at 8:30pm.

- Calculus -
**Damon**, Monday, June 27, 2011 at 8:36pmdx/dt = .025 x

dx/x = .025 dt

ln x = .025 t + c

x = e^(.025 t+c) = e^c e^.025 t

so x = C e^.025 t

at t= 0, x = C e^0 = C

when is x = 2C ???

2C = C e^.025 x

e^.025 x = 2

.025 x = ln 2 = .6931

x = 27.7 years

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