Starting with a 2.0 M NaOH solution, determine how you would prepare 1 L of a 0.1 M NaOH solution.
0.5
M1V1=M2V2
This answer doesn't tell how to prepare it and I don't think the number is right.
2 x V1 = 0.1 x 1000
V1 = 0.1 x 1000/2 = 50 mL.
To prepare, accurately pipet 50 mL of the 2 M NaOH into a clean 1 L volumetric flask, make to the mark with distilled water, thoroughly mix.
To prepare a 0.1 M NaOH solution from a 2.0 M NaOH solution, you need to dilute the original solution to a lower concentration.
Here are the steps to prepare 1 L of a 0.1 M NaOH solution:
1. Calculate the amount of solute (NaOH) needed:
- molarity (M1) × volume (V1) = molarity (M2) × volume (V2)
- M1 = 2.0 M (the initial concentration of NaOH)
- V1 = unknown (volume of the original solution)
- M2 = 0.1 M (the desired concentration of NaOH)
- V2 = 1 L (the final volume of the diluted solution)
Rearrange the equation to solve for V1:
V1 = (M2 × V2) / M1
V1 = (0.1 M × 1 L) / 2.0 M
V1 = 0.05 L = 50 mL
2. Measure 50 mL of the 2.0 M NaOH solution using a graduated cylinder or pipette.
3. Transfer the measured 50 mL of the 2.0 M NaOH solution into a 1 L volumetric flask using a funnel.
4. Add distilled water to the volumetric flask gradually while swirling to ensure proper mixing.
5. Continue adding distilled water until the total volume reaches 1 L. The final volume should be measured at the mark on the neck of the volumetric flask.
6. Close the flask with a stopper or a cap and mix the solution thoroughly by inverting the flask several times.
Now, you have successfully prepared 1 L of a 0.1 M NaOH solution from the 2.0 M NaOH solution. Remember to label the flask with the concentration and date for future use.