B is the midpoint of segment AC. AB = 5x and BC = 3x + 4. Find AB, BC and AC.

5x = 3x +4

-3x -3x
2x= 4
/2 /2
x =2
so Ab is 5 *2 which is 10 and BC is 10 and ac is 20

To find the lengths of AB, BC, and AC, we can use the concept of a midpoint.

Since B is the midpoint of segment AC, we can set up an equation using the Midpoint Formula:

Midpoint = (x₁ + x₂)/2 , (y₁ + y₂)/2

In this case, the coordinates of point B represent the midpoint, and the coordinates of points A and C represent the endpoints.

Let's assign a value to x and solve for AB, BC, and AC:

Let x = 1, for example.

AB = 5x = 5(1) = 5
BC = 3x + 4 = 3(1) + 4 = 7
AC = AB + BC = 5 + 7 = 12

Therefore, AB = 5, BC = 7, and AC = 12 when x is 1.

To find the lengths of AB, BC, and AC, you need to use the given information that B is the midpoint of segment AC and the expressions for AB and BC.

Since B is the midpoint of segment AC, it means that AB and BC have equal lengths. So we can set up an equation to represent this:

AB = BC

Now, let's substitute the expressions for AB and BC into the equation:

5x = 3x + 4

To solve for x, we can start by subtracting 3x from both sides:

5x - 3x = 3x + 4 - 3x

2x = 4

Next, we divide both sides of the equation by 2 to solve for x:

2x/2 = 4/2

x = 2

Now that we have the value of x, we can substitute it back into the expressions for AB and BC to find the lengths of these segments:

AB = 5x = 5(2) = 10

BC = 3x + 4 = 3(2) + 4 = 6 + 4 = 10

So, AB = 10, BC = 10, and since B is the midpoint of AC, AC = 2AB = 2(10) = 20.

if b is the midpoint of AC,AC =CD, AB =3x+4,AC= 11x -17, and CE= 49, find DE.