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April 18, 2015

April 18, 2015

Posted by **lori** on Monday, June 27, 2011 at 11:35am.

A = {b, l, a, z, e, r}, B = {b, a, l, e}, C = {a, b, l, e}, D = {l, a, b}, E = {a, b, l}

(Points : 2)

E ⊂ C

C ⊆ B

D ⊆ C

B ⊆ C

C ⊆ D

- geometry -
**MathMate**, Tuesday, June 28, 2011 at 7:29am⊂ means a proper subset.

E⊂C means E is a proper subset of C, or "all elements of E are in C, AND E≠C".

C = {a, b, l, e}, E = {a, b, l}

Since a,b,l are in C, and E≠C, the statement is true.

There is one statement where the number members of the subset exceeds that of the set, which is impossible.

Can you find the statement?

**Answer this Question**

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