Posted by lori on Monday, June 27, 2011 at 11:35am.
Given the following sets, select the statement below that is NOT true.
A = {b, l, a, z, e, r}, B = {b, a, l, e}, C = {a, b, l, e}, D = {l, a, b}, E = {a, b, l}
(Points : 2)
E ⊂ C
C ⊆ B
D ⊆ C
B ⊆ C
C ⊆ D

geometry  MathMate, Tuesday, June 28, 2011 at 7:29am
âŠ‚ means a proper subset.
EâŠ‚C means E is a proper subset of C, or "all elements of E are in C, AND E≠C".
C = {a, b, l, e}, E = {a, b, l}
Since a,b,l are in C, and E≠C, the statement is true.
There is one statement where the number members of the subset exceeds that of the set, which is impossible.
Can you find the statement?
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