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Posted by **Kalleigh** on Sunday, June 26, 2011 at 8:34pm.

x - 5y=10

2x - 10y=20

- Algebra 1 -
**bobpursley**, Sunday, June 26, 2011 at 8:56pmThe equations are the same (divide the second equation by 2). There is no solution.

- Algebra 1 -
**Jai**, Sunday, June 26, 2011 at 8:56pmto do substitution: you choose one equation, then represent one of the variables in terms in terms of the other. and finally substitute it the the other equation.

(1) x - 5y = 10

(2) 2x - 10y = 20

here, let's choose equation (1), and let's represent x in terms of variable y:

x - 5y = 10

x = 5y + 10

then we substitute this to equation (2):

2x - 10y = 20

2(5y + 10) - 10y = 20

10y + 20 - 10y = 20

20 = 20

note that when you come with this answer (constant = constant), this means that the lines are coinciding, meaning any point can be a solution, because the equations are "equal". if you observe equation (2), we can factor out 2:

2x - 10y = 20

2(x - 5y) = 2(10)

x - 5y = 10

it becomes equation (1).

hope this helps~ :)

- Algebra 1 -
**Anonymous**, Wednesday, January 23, 2013 at 7:02pmX+4y=8

2x-5y=29

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