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November 28, 2014

November 28, 2014

Posted by **colton** on Sunday, June 26, 2011 at 5:36pm.

1. What volume of stone is needed to form a solid pyramid with these dimensions?

The surface of the pyramid was originally faced with limestone.

2. How many square meters of facing limestone were needed?

- math -
**Henry**, Monday, June 27, 2011 at 2:46pm1. V = Ab*h/3. Ab = Area of the base.

V = (230)^2 * 146/3 = 2,574,467m^3.

2. Al = P*Hs / 2.

P = 4 * 230 = 920m = Perimeter of the base.

Hs^2 = (b/2)^2 + h^2,

Hs^2 = (230 / 2)^2 + (146)^2 = 34,541

Hs = 186m = Slant Height.

Al = 920 * 186 / 2 = 85,560m^2 = Lateal

area = Amount of limestone needed.

- math -
**gdilla**, Tuesday, November 1, 2011 at 2:11pmHow many square meters of facing limestone were needed?

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