Posted by Luis on Saturday, June 25, 2011 at 11:11pm.
Actually, the solution will involve the G constant. You will have to use it to compute the mass, unless you use Kepler's third law in a different form the involves the sum of the masses of the two objects, in terms of solar mass. "G" is already "built in" to that solution
Equal-mass stars revolve in orbits (circular in this case) about a point midway between the stars. The radius of each star's orbit is d/2, where d is the interstellar separation, 10^12 m.
Centripetal force = Gravity force
Let either mass be m.
G*m^2/d^2 = m*V^2/(d/2)= 2m*V^2/d
or G*m/d = 2*V^2
V*Period = 2*pi*d/2 = pi*d
Eliminate V from the first equation, using V from the second equation, and solve for the mass, m
V = pi*d/Period = 9573 m/s
m = 2*d*V^2/G
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